A basketball is the shape of a sphere.
The volume of a sphere is given by
[tex]V= \frac{4}{3} \pi r^3[/tex]
Given that the diameter of the basketball is 10 in., thus the radius is 10 / 2 = 5 in.
Thus, the volume of the basketball is given by
[tex]V= \frac{4}{3} \pi(5)^3 \\ \\ = \frac{4\times125}{3} \pi=523.6\ in^3[/tex]
Therefore, The best approximate of the volume of the basketball is [tex]5\times10^2\ in^3[/tex]
