Respuesta :
Area of larger circle: 3.14 x 5^2 = 78.5
Area of small circle: 3.14 x 2^2 = 12.56
Difference of the 2 areas: 78.5 - 12.56 = 65.94
Probability of being in large circle but not small circle: 65.94 / 78.5 = 0.84 = 84%
The answer is A) 84%
Area of small circle: 3.14 x 2^2 = 12.56
Difference of the 2 areas: 78.5 - 12.56 = 65.94
Probability of being in large circle but not small circle: 65.94 / 78.5 = 0.84 = 84%
The answer is A) 84%
Short answer: 84% A
Remark
This sounds like there are only 2 circles that matter. The small one is inside the larger and the small one is shaded.
Step One
Find the area of the small circle.
Givens
r = 2
pi = 3.14
Formula
A = pi*r*r = pi r^2
Sub and Solve
A = 3.14 * 2^2
A = 12.56
Step Two
Find the area of the larger circle
A = pi*r^2
pi = 3.14
r = 5
Area = 3.14 * 5^2
Area = 3.14 * 25
Area = 78.5
Step Three
Find the area of the unshaded region between the larger and smaller circles.
Formula
Area unshaded region = Area of the Large Circle - The area small circle
Givens
Area Large Circle = 78.5
Area Small Circle = 12.56
Solve
Area of unshaded region = 78.5 - 12.56 = 65.94
Find the probability of a point being in the unshaded region.
P(unshaded region) = (Area of Unshaded region / Entire Area)*100%
P(unshaded region) = (65.94 / 78.5) *100%
P(unshaded region) = 84%
Answer: A <<<< 84%
Remark
This sounds like there are only 2 circles that matter. The small one is inside the larger and the small one is shaded.
Step One
Find the area of the small circle.
Givens
r = 2
pi = 3.14
Formula
A = pi*r*r = pi r^2
Sub and Solve
A = 3.14 * 2^2
A = 12.56
Step Two
Find the area of the larger circle
A = pi*r^2
pi = 3.14
r = 5
Area = 3.14 * 5^2
Area = 3.14 * 25
Area = 78.5
Step Three
Find the area of the unshaded region between the larger and smaller circles.
Formula
Area unshaded region = Area of the Large Circle - The area small circle
Givens
Area Large Circle = 78.5
Area Small Circle = 12.56
Solve
Area of unshaded region = 78.5 - 12.56 = 65.94
Find the probability of a point being in the unshaded region.
P(unshaded region) = (Area of Unshaded region / Entire Area)*100%
P(unshaded region) = (65.94 / 78.5) *100%
P(unshaded region) = 84%
Answer: A <<<< 84%