The problem can be solved in different ways.
Applying a rule of three we have:
6 servings ---------------> 2-quart pot
x ---------------------------> 12-quart pot
Clearing the value of x we have:
[tex] x = (\frac{12}{2}) * (6)
x = 36
[/tex]
Using ratios can also be solved in two ways:
Way 1:
Service relationship to quart pot:
[tex] \frac{6}{2} =\frac{f}{12}
[/tex]
Clearing f we have:
[tex] f = (\frac{6}{2}) * (12)
f = 36
[/tex]
Way 2:
Relationship of quart pot to services:
[tex] \frac{2}{6}= \frac{12}{f}
[/tex]
Clearing f we have:
[tex] f = (\frac{6}{2}) * (12)
f = 36
[/tex]
Answer:
The two methods are correct.
