Calculate the amount of energy in joules that would be produced if 2.50 x 10^-3 kilogram of matter was entirely converted to energy.

To solve the problem, we can use the Einstein's famous equivalence between energy and mass:
[tex]E=mc^2[/tex]
where
E is the energy
m is the mass
c is the speed of light

In this problem, the mass of the substance is [tex]m=2.50 \cdot 10^{-3} kg[/tex], so if all this mass would be converted in energy, we would have an energy of
[tex]E=mc^2=(2.50 \cdot 10^{-3} kg)(3 \cdot 10^8 m/s)^2=2.25 \cdot 10^{14} J[/tex]

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snehashish65 snehashish65 · Answer 2 · 2022-03-22T03:50:11+01:00

In the universe, mass and energy are two dependent elements, as one occurs from the other. The amount of energy produced from the given mass is [tex]2.25 \times 10^{14} \;\rm J[/tex].

What is Einstein's mass-energy equivalence?

As per Einstein's mass-energy equivalence relation, "Mass and Energy both are convertible into each other". Hence, this relation supports the mass-energy conservation principle.

Given data -

The mass of water is, [tex]m = 2.50 \times 10^{-3} \;\rm kg[/tex].

Apply Einstein's mass-energy equivalence relationship as,

[tex]E = mc^{2}[/tex]

Here,

E is the energy and c is the speed of light.

Solving as,

[tex]E = (2.50 \times 10^{-3}) \times (3 \times 10^{8})^{2}\\\\E = 2.25 \times 10^{14} \;\rm J[/tex]

Thus, we can conclude that the amount of energy produced from the given mass is [tex]2.25 \times 10^{14} \;\rm J[/tex].

Learn more about the mass-energy relation here:

https://brainly.com/question/111650