part 1) Find the area
we know that
the area of the triangle is
A=b*h/2
in this problem
b=9
h=12
so
A=9*12/2-----> A=54 units²
the answer part 1) is
Area=54 units²
Part 2) Find the area of the kite
see the picture attached with letters to better understand the problem
we know that
The area of a Kite is half the product of the diagonals
step 1
find CB
applying Pythagoras Theorem
AB²=AC²+BC²------> BC²=AB²-AC²-----> BC²=5²-3²----> BC²=16
BC=4
so
the diagonals are
(10+4) and (3+3)---------> 14 and 6
Area=(1/2)*[14*6]----> Area=42 units²
the answer Part 2) is
the area of a kite is 42 units²
