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What is the molarity of a solution that contains 125 g nacl in 4.00 l solution? (molar mass of nacl = 58.44 g/mol)
a. 0.535 m
b. 2.14 m
c. 8.56 m
d. 31.3 m?

Respuesta :

Willchemistry
Number of moles solute:

n = m / mm

n = 125 / 58.44

n = 2.138 moles of NaCl

Molarity = moles of solute / volume ( L )

M = 2.138 / 4.00

M = 0.535 M

Answer A

The study of the chemical and bonds is called chemistry. The moles are used to calculate the quantity present or required in the reaction.

The correct answer to the question is option A which is 0.535m.

What are moles?

  • The mole is the base unit of the amount of substance in the International System of Units.
  • It is defined as exactly [tex]6.02214076*10^{23}[/tex] elementary entities, which may be atoms, molecules, ions, or electrons.

All the data is given in the question, the solution to the numerical is as follows:-

[tex]n = \frac{m}{mm} \\ n = \frac{125}{58.44} \\ n = 2.138 moles of NaCl\\ [/tex]

The formula of molarity is as follows:-

[tex]Molarity = \frac{moles\ of\ solute}{volume} ( L ) [/tex]

[tex]M = \frac{2.138}{4.00} M = 0.535 M [/tex]

Hence, the correct answer is 0.535.

For more information about the moles, refer to the link:-

https://brainly.com/question/15209553

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