Answer:
This function has a minimum value(vertex) =(4,-32)
Step-by-step explanation:
When you have an quadratic function, you have yo know that there is a General function that describe it:
y=a^2+bx-c
If you have that a>0, then your function has a minimum that is the same than the vertex.
You can calculate the minimum (x1,y1) with this equations:
[tex]x1=-b/2a[/tex]
[tex]y1=4ac-b^2/4a[/tex]
Then you have: y=x^2-8x-16
where:
a=1
b=-8
c=-16
the minimum is:
[tex]x1=-b/2a=-(-8)/(2*1)=8/2=4[/tex]
[tex]y1=4ac-b^2/4a=(((4)(1)(-16))-(-8^2))/4(1)=-32[/tex]
