2 Mg + Oâ‚‚ --> 2 MgO
If we have 6 moles of magnesium, then we use the ratios from the balanced equation to find the moles of oxygen needed
MOLES Oâ‚‚ = MOLES MG * (1 Oâ‚‚ / 2 Mg) <--- we get this from equation
                   = 6 mol Mg * (1 O₂ / 2 Mg)
                   = 3 mol Oâ‚‚Â
We need 3 moles of oxygen otherwise we will not have all 6 moles of magnesium react. This will product
MOLES MgO = MOLES MG * (2 MgO / 2 Mg)
                        = 6 mol Mg * (2 MgO / 2 Mg)
                        = 6 mol MgO
We will produce 6 moles of magnesium oxide