Respuesta :
the complete question in the attached figure
we know that
0° < angle theta < 90°
so
angle theta belong to the first quadrant
sin theta and cos theta are positive
cos theta=0.3090
cos²theta+sin²theta=1
step 1
find sin theta
sin²theta=1-cos²theta------> 1-(0.3090)²-----> sin²theta=0.904519
sin theta=√0.904519------> sin theta=0.9511
the answer part a) is
sin theta=0.9511
step 2
find tan theta
tan theta=sin theta/cos theta-----> tan theta=0.9511/0.3090
tan theta=3.0780
the answer part b) is
tan theta=3.0780
the final answer is
sin theta=0.9511
tan theta=3.0780
we know that
0° < angle theta < 90°
so
angle theta belong to the first quadrant
sin theta and cos theta are positive
cos theta=0.3090
cos²theta+sin²theta=1
step 1
find sin theta
sin²theta=1-cos²theta------> 1-(0.3090)²-----> sin²theta=0.904519
sin theta=√0.904519------> sin theta=0.9511
the answer part a) is
sin theta=0.9511
step 2
find tan theta
tan theta=sin theta/cos theta-----> tan theta=0.9511/0.3090
tan theta=3.0780
the answer part b) is
tan theta=3.0780
the final answer is
sin theta=0.9511
tan theta=3.0780
