for points A, B, and C, AB = 2, BC = 3, and AC = 4. Select one: a. A, B, and C are noncollinear. b. A, B, and C form a right triangle. c. A, B, and C are collinear. d. A, B, and C form an equilateral triangle.

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23-06-2018
Mathematics

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for points A, B, and C, AB = 2, BC = 3, and AC = 4. Select one: a. A, B, and C are noncollinear. b. A, B, and C form a right triangle. c. A, B, and C are collinear. d. A, B, and C form an equilateral triangle.

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jcherry99 jcherry99 · Answer 1 · 2018-06-23T04:18:56+02:00

Short Answer: A
Remark
C
Let's start with the false choices.
If they were colinear, then if AB + BC would = 5 or 1 depending on the location of C. Answer C is not correct.

B
a b and c do not form a right triangle. a^2 + b^2 ≠ c^2
2^2 + 3^2 = 13 not 16 (which is what c^2 or 4^2 = )

D
D is false. Equilateral triangles have 3 equal sides.

A is true. Since A and C are opposites and you have eliminated C by arguing A. Then A must be the answer.