Answer:
option C
Step-by-step explanation:
The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity. The acceleration due to gravity is –9.8 m/s2
An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.
g= -9.8, v0 = 20 and h0 = 60
So the equation becomes
[tex]h(t)= -9.8t^2 +20t +60[/tex]
When the object hit the ground the height =0 so we replace h(t)=0
Apply quadratic formula
[tex]t= \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
a= -9.8 , b=20 and c= 60
[tex]t= \frac{-20+-\sqrt{(20)^2-4(-9.8)(60)}}{2(-9.8)}[/tex]
