Respuesta :
                   2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
  from the reaction   2 mol               4 mol
from the problem   5.4 mol             10.8 mol
M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 ≈480 = 4.8 * 10² g
Answer is C. 4.8*10² g.
  from the reaction   2 mol               4 mol
from the problem   5.4 mol             10.8 mol
M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 ≈480 = 4.8 * 10² g
Answer is C. 4.8*10² g.
Answer : The mass of [tex]CO_2[/tex] formed will be, [tex]4.8\times 10^2g[/tex]
Explanation :
The balanced chemical reaction will be:
[tex]2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)[/tex]
First we have to calculate the moles of [tex]CO_2[/tex].
From the reaction, we conclude that
As, 2 mole of [tex]C_2H_2[/tex] react to give 4 mole of [tex]CO_2[/tex]
So, 5.4 moles of [tex]C_2H_2[/tex] react to give [tex]\frac{4}{2}\times 5.4=10.8[/tex] moles of [tex]CO_2[/tex]
Now we have to calculate the mass of [tex]CO_2[/tex]
[tex]\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2[/tex]
[tex]\text{ Mass of }CO_2=(10.8moles)\times (44g/mole)=475.2g=4.8\times 10^2g[/tex]
Therefore, the mass of [tex]CO_2[/tex] formed will be, [tex]4.8\times 10^2g[/tex]
