Respuesta :
You have a system [tex] \left \{ {{2x-3y=-1} \atop {11x-9y=-13}} \right. [/tex].
When the first equations is multiplied by -3, the sum of the two equations is equivalent to 5x =-10.
When the first equations is multiplied by 11 and the second equation is multiplied by -2, the sum of the two equations is equivalent to -15y =15.
Then the system [tex] \left \{ {{5x =-10} \atop {-15y =15}} \right. [/tex] is equivalent to the initial system and has the same solution (-2,-1).
When the first equations is multiplied by -3, the sum of the two equations is equivalent to 5x =-10.
When the first equations is multiplied by 11 and the second equation is multiplied by -2, the sum of the two equations is equivalent to -15y =15.
Then the system [tex] \left \{ {{5x =-10} \atop {-15y =15}} \right. [/tex] is equivalent to the initial system and has the same solution (-2,-1).
The system of equations will also have a solution of (-2,-1) will be 5x = -10 and -15y = 15.
What is the linear system?
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The solution to the system of equations below is (-2,-1).
2x - 3y = - 1   …1
11x - 9y = - 13  …2
When the first equations is multiplied by -3,the sum of the two equations is equivalent to 5x =-10.
When the first equations is multiplied by 11 and the second equation is multiplied by -2, the sum of the two equations is equivalent to -15y =15.
Then the system of equations will also have a solution of (-2,-1) will be 5x = -10 and -15y = 15.
More about the linear system link is given below.
https://brainly.com/question/20379472
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