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PBCHEM
Answer : To calculate the number of moles of copper (II) chloride in 15.0 ml of 0.500 M solution, you have to simply use the given calculation:

15 (ml)   X   0.500 (moles) / 1000 (mL) = 0.00750 moles of CuCl₂ .


igeclement43

Answer: The number of moles of Copper (II) chloride is 0.0075mol.

Explanation:

From the definition of molarity, it is the number of moles of solute in 1L or 1dm³ of a solution. It has the unit of mol/dm³ or mol/L or simply M

It can be expressed as

Molarity = moles of solute / volume of solution

Given that ;

molarity =0.50M

Volume of solution =15mL= 15× 10^-3

moles of solute (Copper (II) Chloride) =?

0.50 = moles of solute /15×10^-3

Moles = 0.50 × 15×10^-3

Moles = 7.5 ×10^-3mole

Therefore moles of Copper (II) chloride = 0.0075mol.

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