Respuesta :
C= (3, -5) aND D= (6, 0)
y-y1 = m (x -x1).
i.e. if x1, y1 = 3, -5 and x2, y2 = 6,0 then#
y- (-5) = m(x - 3), so all we are missing is the slope:
Y2 -y1
--------------- = m (the slope)
x2 -x1
0-(-5)
------- = 0+5 /3 = 5/3
6 - 3
therefore equation of line is y+5 = 5/3 (x - 3)
y-y1 = m (x -x1).
i.e. if x1, y1 = 3, -5 and x2, y2 = 6,0 then#
y- (-5) = m(x - 3), so all we are missing is the slope:
Y2 -y1
--------------- = m (the slope)
x2 -x1
0-(-5)
------- = 0+5 /3 = 5/3
6 - 3
therefore equation of line is y+5 = 5/3 (x - 3)
Hello!
To solve, we need to first find the slope of the line. We can do this by using the formula y2-y1/x2-x1. We can switch the ones and twos and the slope will be the same. We will have (3,-5) be (x1,y1) and have (6,0) be (x2,y2). Now we will plug it into the formula.
0+5/6-3
5/3
Our slope is 5/3, and now we will put it into the slope intercept equation.
y=5/3x+b
Now we will select a point on our line (6,0) and plug it into the equation and solve for b.
0=5/3(6)+b
0=10+b
0-b=10
b=-10
Now we can put it in slope intercept form.
y=5/3x-10
Just to check, we will plug in 3 and see if it equals -5.
y=5/3(3)-10
y=5-10
y=-5
The equation for the line CD is y=5/3x-10
I hope this helps!
To solve, we need to first find the slope of the line. We can do this by using the formula y2-y1/x2-x1. We can switch the ones and twos and the slope will be the same. We will have (3,-5) be (x1,y1) and have (6,0) be (x2,y2). Now we will plug it into the formula.
0+5/6-3
5/3
Our slope is 5/3, and now we will put it into the slope intercept equation.
y=5/3x+b
Now we will select a point on our line (6,0) and plug it into the equation and solve for b.
0=5/3(6)+b
0=10+b
0-b=10
b=-10
Now we can put it in slope intercept form.
y=5/3x-10
Just to check, we will plug in 3 and see if it equals -5.
y=5/3(3)-10
y=5-10
y=-5
The equation for the line CD is y=5/3x-10
I hope this helps!
