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As the kid rises to a height of 0.925 meters, his velocity decreases at the rate of 9.8 m/s each second. At the maximum height, his velocity is 0 m/s. Use the following equation to solve this problem.
vf^2 = vi^2 + 2 * a * d, vf = 0, a = -9.8
0 = vi^2 + 2 * -9.8 * 0.925
vi = √18.13
This is approximately 4.26 m/s.
I hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)
vf^2 = vi^2 + 2 * a * d, vf = 0, a = -9.8
0 = vi^2 + 2 * -9.8 * 0.925
vi = √18.13
This is approximately 4.26 m/s.
I hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)
4.26 m/s was his speed when he left the trampoline.
Speed
Speed exists as a scalar quantity that guides "how fast an object is moving." Speed can be considered as the rate at which an object covers distance. A fast-moving object contains a high speed and covers a relatively large distance in a short amount of time.
As the kid increases to a height of 0.925 meters, his velocity declines at the rate of 9.8 m/s each second. At the maximum height, his velocity stands 0 m/s. Use the following equation to solve this problem.
[tex]vf^2 = vi^2 + 2 * a * d[/tex]
vf = 0,
a = -9.8
[tex]0 = vi^2 + 2 * -9.8 * 0.925[/tex]
[tex]vi = \sqrt{} 18.13[/tex]
This is approximately 4.26 m/s.
Hence, 4.26 m/s was his speed when he left the trampoline.
To learn more about Speed refer to:
https://brainly.com/question/13262646
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