Which of the following functions best describes this graph?

The equation of the following graph is y = ( x - 2 ) ( x - 2 )
The quadratic function has the following general equation:
[tex]\large {\boxed {f(x) = ax^2 + bx + c} }[/tex]
If x₁ and x₂ are the roots of a function of a quadratic equation, then:
[tex]\large {\boxed {f(x) = a(x - x_1)(x - x_2) } }[/tex]
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using:
From the value of Discriminant , we know how many solutions the equation has by condition:
Let us tackle the problem.
From the attached image, there are 2 points passed by the graph that are (0 , 4) and (2 , 0).
This graph only has one real root that is (2 , 0) → x₁ = x₂ = 2 .
We can find the function with the following formula:
[tex]y = a (x - x_1) (x - x_2)[/tex]
[tex]y = a (x - 2) (x - 2)[/tex]
The graph pass through ( 0 , 4 ) , then :
[tex]y = a (x - 2) (x - 2)[/tex]
[tex]4 = a (0 - 2) (0 - 2)[/tex]
[tex]4 = a (4)[/tex]
[tex]a = 4 \div 4 [/tex]
[tex]\boxed {a = 1}[/tex]
[tex]y = 1 (x - 2) (x - 2)[/tex]
[tex]\large {\boxed {y = (x - 2) (x - 2)} }[/tex]
Grade: College
Subject: Mathematics
Chapter: Quadratic Equations
Keywords: Equation , Line , Variable , Line , Gradient , Point , Quadratic , Intersection