Set up the integral that uses the method of disks/washers to find the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 1 16 x2, x = 5, y = 0; about the y-axis
The area of a washer is pi times the difference of the squares of the outer and inner radii. Your integral can be written as [tex] \int\limits^\frac{25}{16}_0 {\pi(5^2-16y)} \, dy [/tex]
