As the variation is direct then we have the following expression:
[tex]y = kx ^ 2
[/tex]
From here, we clear the value of k.
For this we use the following data:
y = 144 when x = 4
Substituting values:
[tex]144 = k4 ^ 2
[/tex]
Clearing k we have:
[tex]k = 144/4 ^ 2
k = 144/16
k = 9[/tex]
Then, the function is:
[tex]y = 9x ^ 2
[/tex]
When x = -5 we have:
[tex]y = 9 (-5) ^ 2
y = 9 (25)
Y = 225[/tex]
Answer:
the value of y when x = -5 is:
b.
225