Respuesta :
Let's call the numerator [tex] x [/tex]. Since the denominator is four more than three times the numerator, it means that it equals [tex] 3x+4 [/tex]. So, the original fraction is
[tex] \frac{x}{3x+4} [/tex]
Note that this implies that [tex] x \neq \frac{-4}{3} [/tex], otherwise the denominator would be zero. Now, we need to increase both numerator and denominator by 4, obtaining this new fraction:
[tex] \frac{x+4}{3x+4+4} = \frac{x+4}{3x+8} [/tex]
Note that this implies that [tex] x \neq \frac{-8}{3} [/tex], otherwise the denominator would be zero. And we know that this equals 925 (assuming that 925925 is some kind of typo/formatting error). This leads to the equation
[tex] \frac{x+4}{3x+8} = 925[/tex]
Since we assumed that the denominator is not zero, we can multiply both sides by it, so that the equation becomes
[tex] x+4 = 925(3x+8) = 7400 + 2775 x [/tex]
Subtract 4 from both sides to get
[tex] x = 7396 + 2775 x [/tex]
Subtract 2775x from both sides to get
[tex] -2774 x = 7396 [/tex]
Finally, divide both sides by -2774 to get
[tex] x = \frac{7396}{-2774} [/tex]
