[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad \qquad \qquad
slope = m\implies \cfrac{5}{8}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-3)=\cfrac{5}{8}(x-2)
\\\\\\
y+3=\cfrac{5}{8}x-\cfrac{5}{4}\implies y=\cfrac{5}{8}x-\cfrac{5}{4}-3\implies y=\cfrac{5}{8}x-\cfrac{17}{4}[/tex]
[tex] \bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{8}}{8y=5x-34}\implies -5x+8y=-34
\\\\\\
\stackrel{\textit{multiplying both sides by -1}}{5x-8y=34}\impliedby standard~form [/tex]
bear in mind that in a standard form of a linear equation
the variables are both on the left side, "x" before the "y" usually.
"x" cannot have a negative coefficient.
all coefficients and constants must be integers.
