We know:
the sum of measures of these three angles of any triangle is invariably equal 180°.
Therefore we have the equation:
[tex](40x-27)+(25-2x)+(26+x)+180\\\\(40x-2x+x)+(-27+25+26)=180\\\\39x+24=180\ \ \ |-24\\\\39x=156\ \ \ \ |:39\\\\x=4[/tex]
Substitute the value of x to the equations:
[tex]a=40x-27\to a=40(4)-27=133\\b=25-2x\to b=25-2(4)=17\\c=26+x\to c=26+4=30[/tex]
Answer: A) a= 133 b= 17 c=30
