Given , h = -16[tex] t^{2} [/tex] + 50t where h is the height of the rocket in feet and t is the time in seconds after liftoff.
The rocket will remain in the air till it reaches the ground.
To find the time taken to reach the maximum height we use a formula
t = [tex] \frac{-b}{2a} [/tex]
From the given equation , a= -16 , b= 50
Apply the values in the formula
t = [tex] \frac{-50}{2(-16} [/tex]
t = 1.5625 seconds
The rocket will reach the maximum point in 1.5625 seconds and it reaches the ground in another 1.5625 seconds.
1.5625 + 1.5625 = 3.125 seconds
The rocket will remain in the air for 3.1 seconds