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If one card is randomly chosen from a standard deck, what is the probability that a 6 or a diamond is chosen?
A. 7/52
B. 16/52
C. 17/52
D. 1/52

Respuesta :

konrad509

[tex] |\Omega|=52\\
|A|=\underbrace{4}_{\text{a six}}+\underbrace{13}_{\text{a diamond}}-\underbrace{1}_{\text{a six of diamonds}}=16\\\\
P(A)=\dfrac{16}{52}\Rightarrow {\text{B}} [/tex]

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