Respuesta :
Here we can use ampere'a law to find the magnetic field
[tex]\int B.dl = \mu_o i_{en}[/tex]
[tex]B*2 \pi r = \mu_o (i_1 + \frac{i_2*\pi(3^2 - 2^2)}{\pi(4^2 - 2^2}[/tex]
[tex]B*2 \pi*0.003 = 4\pi * 10^{-7} (12 + 5)[/tex]
[tex]B = 4\pi * 10^{-7} (12 + 5)[/tex]
[tex] B = 1.13 * 10^{-3} T[/tex]
The magnetic field is the type of field where the magnetic force is obtained. The magnitude of the magnetic field is 3.0 mm from the axis will be 1.13×10⁻³T.
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The ampere law is given by;
[tex]\int\limits {B} \, dL= \mu_0 i \\\\ B\times 2 \pi r= \mu_0( i_1+i_2(\pi(r_2^2-r_1^2) \\\\ B\times 2 \times 3.14 0.003= 4\pi \times 10^{-7}(12+5) \\\\ \rm B= 1.13 \times 10^{-3} \ T[/tex]
Hence the magnitude of the magnetic field is 3.0 mm from the axis will be 1.13×10⁻³T.
To learn more about the megnetic field refer to the link;
https://brainly.com/question/19542022
