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The sum Of the digits of a two digit number is 13. If the number obtained by reversing the digits exceeds the original number by 27 find the number

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konrad509

[tex] x+y=13\\
10y+x=10x+y+27\\\\
x+y=13\\
9x-9y=-27\\\\
x+y=13\\
\underline{x-y=-3}\\
2x=10\\
x=5\\\\
5+y=13\\
y=8\\\\
\boxed{10\cdot5+8=58}
[/tex]

Kvell
The answer is 8+5. or 5+8 depending on your preferences

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