Respuesta :

check the picture below. for the pre-edition version.


as for the edition above


[tex] \bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad
(\stackrel{x_2}{-4}~,~\stackrel{y_2}{-4})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-4-2}{-4-0}\implies \cfrac{-6}{-4}\implies \cfrac{3}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=\cfrac{3}{2}(x-0)
\\\\\\
y-2=\cfrac{3}{2}x\implies y=\cfrac{3}{2}x+2 [/tex]

Ver imagen jdoe0001
SvetkaChem

Slope intercept form of the line is

y=mx +b.


m is a slope.

m=(y2 -y1)/(x2 - x1)=(2-(-4))/(0-(-4))=6/4=3/2

m=3/2

y=(3/2)x + b


To find y-intercept, we are going to use point (0,2) and equation y=(3/2)x + b.

2=(3/2)*0 + b,

b = 2.


Actually point (0,2) already is a y-intercept, because it has x=0.


Answer is y=(3/2)x + 2.

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