look at yo periodic table to find the atomic mass
it says that there is 22.98g of sodium (Na) in 1 mol of sodium
1 mol is 6.022 * 10^23 atoms
one way we can do this is ratio and proportion
[tex]\frac{grams_1}{mols_1}=\frac{grams_2}{mols_2}[/tex]
we are solving for [tex]grams_2[/tex]
multiply both sides by [tex]mols_2[/tex]
[tex]\frac{(grams_1)(mols_2)}{mols_1}=grams_2[/tex]
let's say [tex]grams_1[/tex]=22.98g and [tex]mols_1=6.022*10^{23}[/tex] and [tex]mols_2=1.3*10^{21}[/tex]
therefor
[tex]\frac{(22.98g)(1.3&10^{21}mol)}{6.022*10^{23}mol}=grams_2[/tex]
[tex]0.0496081g=grams_2[/tex]
so it weighs about [tex]5.0*10^{-2}g[/tex]
