Respuesta :

DeanR

The midpoint is the middle of the segment, on the segment equidistant from each end.


We compute it by taking the average of the coordinates


[tex]M=\frac 1 2(-3 + -6, 4 + -1) = (- \frac 9 2, \frac 3 2)[/tex]


Choice C

Answer:

Option: C is the correct answer.

                 C.    [tex](-\dfrac{9}{2},\dfrac{3}{2})[/tex]

Step-by-step explanation:

We know that the vertices of the mid point C(x,y) of the line segment AB with vertices as A(a,b) and B(c,d) is given by:

[tex]x=\dfrac{a+b}{2},\ and\ y=\dfrac{c+d}{2}[/tex]

Here we are asked to find the mid point of the line segment joining the point (-6,-1) and (-3,4)

Let C(x,y) be the mid point of this line segment.

Hence, we have:

[tex]x=\dfrac{-6-3}{2},\ and\ y=\dfrac{-1+4}{2}\\\\i.e.\\\\x=\dfrac{-9}{2},\ and\ y=\dfrac{3}{2}[/tex]

Hence, the mid point has vertex:

                  [tex](-\dfrac{9}{2},\dfrac{3}{2})[/tex]

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