one+four+three=eight pens.
Two pens are selected without replacement.
Need probability of selecting two black pens.
Probability of selecting first black pen is four out of eight, 4/8
Probability of selecting second black pen is three remaining black pens out of the remaining 7 pens = 3/7
Probability of both events happening is the product of the two probabilities, according to the multiplication rule.
Therefore probability of selecting two black pens out of the initial eight pens
=(4/8)(3/7)=3/14=0.2143 (to the ten-thousandth).
Rounding to the hundredth will give you the required answer.
Answer: C) 0.21
Step-by-step explanation:
8 total pens....4 are black
first pick, probability of being black is 4/8
2nd pick. without replacing, probability is 3/7
probability of a black pen picked first and then another black pen picked again is : 4/8 * 3/7 = 12/56 = 0.21
HOPE THIS HELPS :)
