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a car slows down -27.7 m/s to -10.9 m/s "while" undergoing a displacement of -105 m what was its acceleration

Respuesta :

Cetacea

Acceleration of car=3.09 m/s²

Explanation:

initial velocity= Vi=-27.7 m/s

Final velocity=-10.9 m/s

displacement=-105 m

using kinematic equation Vf²= Vi² + 2 a d

(-10.9)²=(-27.7)² + 2 a (-105)

-648.5=-210a

a=648.5/210

a=3.09 m/s²

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