Hey!
Here is the equation:
[tex] 5b - 4 = 2b + 17 [/tex]
Add 4 to leave 5b by itself. It becomes:
[tex] 5b = 2b + 21 [/tex]
Subtract 5b from 2b to leave only 1 variable. It becomes:
[tex] 3b = 21 [/tex]
Divide by 3 to leave b by itself
[tex] \frac{3b}{3} = \frac{21}{3} [/tex]
It becomes:
[tex] \framebox{b = 7} [/tex]
