Respuesta :

check the picture below.


so we can use the pythagorean theorem to get the dashed line of the road,


[tex] \bf c=\sqrt{a^2+b^2}\implies c=\sqrt{5^2+9^2}\implies \stackrel{\textit{miles on the map}}{c=\sqrt{106}} [/tex]


we know that Sam doing 30mph, can do that road in 45 minutes, in actual length, well, 45 minutes is 3/4 of an hour, so


[tex] \bf \stackrel{45~mins}{\cfrac{3}{4}\underline{hr}}\cdot \cfrac{30miles}{\underline{hr}}\implies \cfrac{90miles}{4}\implies \cfrac{45}{2}~miles [/tex]


so, that's how many actual miles the road really is, so if we put that in actual : map ratio, we'd get


[tex] \bf actual:map\qquad \cfrac{actual}{map}\implies \cfrac{\quad \frac{45}{2}\quad }{\sqrt{106}}\implies \cfrac{45}{2\sqrt{106}}\textit{ miles per cm} [/tex]


and you know what that is.

Ver imagen jdoe0001

The distance [tex] d [/tex] on the map is the hypothenuse of a right triangle whose legs are 5 and 9. To find it, you can use Pythagorean theorem:


[tex] d = \sqrt{25+81} = \sqrt{106} [/tex]


On the other hand, since 45 minutes are 0.75 hours, driving this amount of time at 30 miles per hour makes you travel


[tex] 0.75 \cdot 30 = 22.5 [/tex] miles.


So, you have that 22.5 miles correspond to [tex] \sqrt{106} [/tex] centimeters. This means that one centimeter corresponds to


[tex] \frac{22.5}{\sqrt{106}} \approx 2.18539\ldots[/tex]


So the closer answer is D