if the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula [tex] c^2=a^2+b^2 [/tex] to find b:
[tex] (20)^2=(18)^2+b^2,\\ b^2=400-324=76 [/tex].
The branches of hyperbola go in y-direction, so the equation of hyperbola is
[tex] \dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1 [/tex].
Substitute a and b:
[tex] \dfrac{y^2}{76}- \dfrac{x^2}{324}=1 [/tex].
