Answer:
The ball rises to a height of 20.4 meters.
Explanation:
Since we know the speed at which the ball starts rising, we can ignore the other data. The height reached by the ball can be obtained using the kinematics equation:
[tex]v^{2}=v_0^{2}-2gy[/tex]
Since the velocity at the highest point is zero, we can solve for the height y at that point:
[tex]y=\frac{v_0^{2}}{2g}[/tex]
Plugging in the given value for the initial velocity, and assuming that the acceleration due to gravity g is 9.8m/s², we obtain:
[tex]y=\frac{(20m/s)^{2}}{2(9.8m/s^{2})}\\\\y=20.4m[/tex]
It means that the ball rises to a height of 20.4 meters.
