Hello there!
[tex] ((((1 - x) - (x^2)) + 5x^2) - 5x) + 5\\ \\ Pull \ out \ like \ factors : \\
4x^2 - 6x + 6 = 2 * (2x^2 - 3x + 3) \\ \\ Factoring \ 2x^2 - 3x + 3 \\ \\ \sf The \ first \ term \ is, \ 2x^2 \ its \ coefficient \ is \ 2 . \\
The \ middle \ term \ is, \ -3x \ its \ coefficient \ is \ -3 .\\
The \ last \ term, \ "the \ constant", \ is \ +3 [/tex]
[tex] \sf Find \ two \ factors \ of \ 6 \ whose \ sum \ equals\ \\ the \ coefficient \ of \ the \ middle \ term, \ which \\is \ -3 . [/tex]
[tex] -6 + -1 = -7 \\
-3 + -2 = -5 \\
-2 + -3 = -5 \\
-1 + -6 = -7 \\
1 + 6 = 7 \\
2 + 3 = 5 \\
3 + 2 = 5 \\
6 + 1 = 7 \\
[/tex]
[tex] \sf Your \ answer:\boxed{\bf{ 2 * (2x^2 - 3x + 3)}} [/tex]
