In the balanced equation, we see that the ratio of [tex] O_{2}:H_{2}O [/tex] is 1:2 respectively. That being said, we can then set up a proportion to solve for the number of moles of water produced from 13.35 moles of oxygen:
[tex] \frac{1mol_{O_{2}}}{2mol_{H_{2}O}} =\frac{13.35mol_{O_{2}}}{xmol_{H_{2}O}} [/tex]
Then we cross multiply and solve for x:
[tex] x=26.7mol_{H_{2}O} [/tex]
Therefore the answer is B) 26.70 mol.
