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in triangle ABC, the measure of angle B is 18° more than three times the measure of angle A. The measure of angle C is 42° more than the measure of angle A. find the measure of each angle.

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tramserran

A = A

B = 3A + 18

C = A + 42

The sum of the angles of a triangle equals 180°

A + B + C = 180

(A) + (3A + 18) + (A + 42) = 180

5A + 60 = 180

5A = 120

A = 24

B = 3A + 18 = 3(24) + 18 = 72 + 18 = 90

C = A + 42 = C = 24 + 42 = 66

Answer: A=24, B=90, C=66

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