If I've read this correctly, it looks like this.
[tex] \dfrac{(x + 1)}{2 - \dfrac{(x + 2)}{3x}} [/tex]
If that is correct, then the first step is to put the top part of the denominator over 3x
[tex] \dfrac{(x + 1)}{\dfrac{6x - (x + 2)}{3x}} = \dfrac{(x + 1)}{\dfrac{5x -2}{3x}} [/tex]
The next part is to flip a three tier fraction. I'm afraid I have to show what happens. My latex is not that strong.
What you get is
[tex] \dfrac{3x*(x + 1)}{(5x - 2)} [/tex]
This is just about your final answer. You could write it as
[tex] \dfrac{3x^2 + 3x}{(5x - 2)} [/tex]
