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At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality 15 + 6s ≤ 90 represents the described cost, where s is the maximum number of sandwiches that could be bought. What is the maximum number of sandwiches Keith can buy?

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It is given in the question that,

At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality

[tex] 15 + 6s \leq 90  [/tex]

represents the described cost, where s is the maximum number of sandwiches that could be bought.

Now we have to solve for s, and for that, we first subtract 15 to both sides, that is

[tex] 6s\leq  75 [/tex]

Dividing both sides by 6

[tex] s\leq  12.5 [/tex]

So the maximum number of sandwiches Keith can buy is 12.

soraiya0209

Answer:

12

Step-by-step explanation:

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