Respuesta :
a, P(A or B) = P(A) + P(B) - P(A and B)
... 0.35 = 0.23 + 0.30 - P(A and B)
... P(A and B) = 0.43 - 0.35
... P(A and B) = 0.08
b. If events A and B are mutually exclusive, P(A and B) = 0. Here, P(A and B) ≠ 0, so the events are not mutually exclusive.
Probabilities are used to determine the chance of an event.
- The probability that he gets both jobs is 0.012
- The events are not mutually exclusive
The probabilities are given as:
[tex]P(A) = 0.23[/tex]
[tex]P(B) = 0.20[/tex]
[tex]P(At\ least\ one) = 0.35[/tex]
(a) Probability that he gets both jobs
First, we calculate the probability that he gets one of the jobs
This is calculated as:
[tex]Pr(One) = P(A) \times P(B') + P(A') \times P(B)[/tex]
So, we have:
[tex]Pr(One) = 0.23 \times (1 - 0.20) + (1 - 0.23) \times 0.20[/tex]
[tex]Pr(One) = 0.338[/tex]
The probability that he gets both job is:
[tex]P(Both) = P(At\ least\ one) - P(One)[/tex]
So, we have:
[tex]P(Both) = 0.35 - 0.338[/tex]
[tex]P(Both) = 0.012[/tex]
(b) Check if the events are mutually exclusive
Two events are said to be mutually exclusive if:
[tex]P(A\ and\ B) = 0[/tex]
In other words,
[tex]P(Both) = 0[/tex]
Hence, the events are not mutually exclusive
Read more about probabilities at:
https://brainly.com/question/11234923