(a)
slope of f(x):
We can select any two points to find slope
(0,-3) and (1,0)
now, we can use slope formula
[tex] m=\frac{y_2-y_1}{x_2-x_1} [/tex]
now, we can plug values
[tex] m=\frac{0+3}{1-0} [/tex]
[tex] m=3 [/tex]
slope of g(x):
[tex] g(x)=4x-5 [/tex]
we can compare it with slope intercept form of line
[tex] g(x)=mx+b [/tex]
we get
[tex] m=4 [/tex]
so, we can see that slope of f(x) is 3 while slope of g(x) is 4
so, slope of g(x) is greater than slope of f(x)
(b)
y-intercept of f(x):
we know that y-intercept is value of y when x=0
we are given point (0,-3)
so, y-intercept is -3
y-intercept of g(x):
we know that y-intercept is value of y when x=0
so, we can plug x=0 and find y
[tex] g(0)=4*0-5 [/tex]
[tex] y=-5 [/tex]
so, y-intercept is -5
Since, -3 is greater than -5
Hence , y-intercept of f(x) has greater value.........Answer