The distance formula is [tex] \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} [/tex]
Our points are:
Using these points, we can solve for the distance as such:
[tex] \sqrt{(4-(-3))^2+(5-(-3))^2}\\ \sqrt{7^2+8^2}\\ \sqrt{49+64}\\ \sqrt{113} [/tex]
The distance between A and B is √113, or approximate 10.63, units.
Next, the midpoint formula is [tex] (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2}) [/tex]
Using our points, we can solve for the midpoint as such:
[tex] (\frac{4+(-3)}{2},\frac{5+(-3)}{2})\\ \\(\frac{1}{2},\frac{2}{2}) \\ \\ (0.5,1) [/tex]
The midpoint of Line AB is (0.5,1).
