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Helen mixes a first solution, 4 liters of 40% concentrated sulfuric acid solution, with a second solution, 5 liters of a sulfuric acid solution with a stronger concentration, and the resultant solution is 9 liters of 50% concentrated sulfuric acid solution. what was the concentration, as a percent, of the second solution?

Respuesta :

The percentage of the second solution would of been 10% as the total of both solutions was 50% and we already knew that the first solution had 40%

Answer: 58%

Explanation:

Formula used :

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

[tex]C_1[/tex] and [tex]C_2[/tex] are the concentrations  of first and second solution respectively

[tex]C_3[/tex] is the concentration of resulting solution

[tex]V_1[/tex] and [tex]V_2[/tex] are the volumes of of first and second solution respectively

[tex]V_3[/tex] is the volume of resulting solution = 9 L

Now put all the given values in the above formula, we get the concentration of resulting solution.

[tex](4\times 40)+(5\times x)=(9\times 50)[/tex]

solving for x, we get

[tex]x=58%[/tex]

The concentration of the second solution= 58%.

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