FlynnH
contestada

How would you find the equation of a line that is perpendicular to y = 3x + 1 and passes through point (1, -1)?

Respuesta :

perpendicular means the slopes of the two lines are opposite reciprocals. Since the slope of y = 3x + 1 is "3", then the opposite reciprocal slope is [tex] \frac{-1}{3} [/tex]

Next, plug in the slope ([tex] \frac{-1}{3} [/tex] )and point (1, -1) into the point-slope formula: y - y₁ = m(x - x₁); where (x₁, y₁) is the point.

y - (-1) = [tex] \frac{-1}{3} [/tex](x - 1)

y + 1 = [tex] \frac{-1}{3} [/tex]x + [tex] \frac{1}{3} [/tex]

y = [tex] \frac{-1}{3} [/tex]x + [tex] \frac{-2}{3} [/tex]