Ismael54
contestada

The length of a rectangle is 4 centimeters less than twice it’s width. The perimeter of the rectangle is 34vm. What are the dimensions of the rectangle?

The length of a rectangle is 4 centimeters less than twice its width The perimeter of the rectangle is 34vm What are the dimensions of the rectangle class=

Respuesta :

TheBreeze

l = 2w - 4

Because we're solving for 2l + 2w, that can be simplified to

2(2w - 4) + 2w = 34

4w - 8 + 2w = 34

6w - 8 = 34

6w = 42

w = 7

Knowing this, we can input w:

2(7) + 2l = 34

14 + 2L = 34

2l = 20

l = 10

L = 10, W = 7, Option C

PenguinHelper

To begin to solve this question, we need to express the lengths in terms of width of the width in terms of length. Since the question says that the length was 4 centimeters less than twice the width, that means that the length is equal to 4 centimeters less (minus) twice the width (times two). That means that l = 2w - 4. We also know that the perimeter is 34cm.

The formula for the area of a rectangle is 2l + 2w, or 2(2w - 4) + 2w. Since the perimeter is 34, that means that:

4w - 8 + 2w = 34

Combining like terms and moving the numbers to the other side, we get:

6w = 42

w = 7

Plugging in the value of w in the formula for the length, we get that l = 2 (7) - 4 = 14 - 4 = 10. That means that the correct answer is C.

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