PLEASE HELP ME!!!!!!!!!!!

f(-3) = x² - 2x + 3
Plug in -3 for x.
(-3)² - 2(-3) + 3
Distribute the exponent inside the parentheses (-3)^2.
9 - 2(-3) + 3
Multiply -2 * -3.
9 + 6 + 3
Solve from left to right;
is your answer.
[tex] f(x) = x^{2} -2x+3 [/tex]
Since x is equal to -3, substitute all the x's with -3.
[tex] (-3)^{2} - 2 \cdot -3 + 3 [/tex]
[tex] Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction [/tex]
Parentheses is first:
[tex] (-3)^{2} = -3 \times -3 = 9 [/tex]
Next is multiplication:
[tex] 2 \times -3 = -6 [/tex]
The new equation is:
[tex] 9-(-6)+3 [/tex]
You start from left to right. When you're subtracting a negative number from a positive, the sign changes and you add and the negative number becomes positive.
[tex] 9-(-6)+3 \rightarrow 9+6+3 [/tex]
Add from left to right:
[tex] 9+6 = 15 [/tex]
Add 3:
[tex] 15+3 = 18 [/tex]
[tex] f(-3) = \bf 18 [/tex]