contestada

Captain calculus can leap over tall buildings. when he does so, his height s (in feet) off the ground after t seconds is given by s(t) = t^2+7t+34. for how many seconds is captain calculus more than 40 feet off the ground?

Respuesta :

we are given

height function as

[tex]s(t) = t^2+7t+34[/tex]

we have to find time at which height is more than 40 feet off the ground

so, we can set up inequality as

[tex]s(t)>40[/tex]

[tex]t^2 +7t+34 >40[/tex]

now, we can simplify it

[tex]t^2 +7t-6 >0[/tex]

Let's assume it is equal to 0

and then we can solve for t

[tex]t^2 +7t-6 =0[/tex]

we can use quadratic formula

[tex] t=0.77200 [/tex]

so,

[tex] t > 0.77200 [/tex]

so, closest value is 1

so, captain calculus more than 40 feet off the ground after 1 seconds.......Answer

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