Horizontal distance between the bullet and the target (s) = 195 m
Horizontal velocity of the bullet (u) = 275 m/s
Time taken to cover the horizontal distance = [tex]\frac{Distance}{velocity}[/tex]
Time taken (t) = [tex]\frac{195}{275}[/tex]
t = 0.709 s
Now, in the vertical direction:
Initial velocity (u) = 0 m/s
Let the depth covered be h.
Time taken (T) = 0.709 s
Acceleration due to gravity (g) = 9.8 m/s^2
Now, using the seconds equation of motion:
[tex]h = ut + \frac{1}{2}at^2[/tex]
[tex]h = 0 +\frac{1}{2}\times 9.8 \times 0.709^2[/tex]
h = 2.463 meters
Hence, the bullet will hit 2.463 meters below the target.
