Respuesta :
When the ball is thrown down with the initial speed of 15 m/s, then its final position is 55.27 m after 2.16 seconds.
How do you calculate the position of the ball?
The position of the ball thrown down is calculated by the formula given below.
[tex]s = s_0 + v_0t + \dfrac {1}{2}at^2[/tex]
Here, s0 is the initial position, v0 is the initial speed, t is the time and a is the acceleration.
Given that, [tex]s_0 = 0[/tex], [tex]v_0 = 15\;\rm m/s[/tex], [tex]t = 2.16\;\rm s[/tex] and [tex]a= g = 9.806\;\rm m/s^2[/tex].
Substituting the values in the above equation,
[tex]s = 0 + 15\times 2.16 + \dfrac{1}{2}\times 9.806\times 2.16^2[/tex]
[tex]s = 55.27 \;\rm m[/tex]
Hence we can conclude that the final position of the ball is 55.27 m.
To know more about the position and velocity, follow the link given below.
https://brainly.com/question/1439172.
